we know that
[surface area of the pyramid]=area of the base+4*[area of one lateral triangle]
area of the base=14*14------> 196 cm²
area of one lateral triangle=b*h/2
b is the length side of the square
b=14 cm
h is the slant height
h=15 cm
area of one lateral triangle=14*15/2-----> 105 cm²
[surface area of the pyramid]=196 cm²+4*[105 cm²]-----> 616 cm²
the answer is
616 cm²
