Molecular weight of CS2 = 76.14 g
number of moles of CS2 = [tex] \frac{weight.of.CS2}{molecular.weight} [/tex]
= [tex] \frac{135}{76.14} [/tex]
= 1.773
Now, 1.733 mol requires 43.2 kj of heat to vaporize.
∴ 1 mol will require [tex] \frac{43.2}{1.77} [/tex] = 24.4 kj/mol
Thus, correct answer is option B