Gay-Lussac's law gives the relationship between pressure and temperature of gas. For a fixed amount of gas, pressure is directly proportional to temperature at constant volume.
P/T = k
where P - pressure , T - temperature and k - constant
[tex] \frac{P1}{T1} = \frac{P2}{T2} [/tex]
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting the values in the equation
[tex] \frac{1100 bar}{T} = \frac{75.5 bar}{298 K} [/tex]
T = 4342 K
initial temperature was 4342 K
