Respuesta :
The generic equation of the line is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
m = (1-6) / (- 6-6)
m = (- 5) / (- 12)
m = 5/12
We choose an ordered pair:
(xo, yo) = (6, 6)
Substituting values:
y-6 = (5/12) (x-6)
y = (5/12) x - 2.5 + 6
y = (5/12) x + 3.5
y = (5/12) x + 7/2
Answer:
the equation of the line is:
y = (5/12) x + 7/2
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
m = (1-6) / (- 6-6)
m = (- 5) / (- 12)
m = 5/12
We choose an ordered pair:
(xo, yo) = (6, 6)
Substituting values:
y-6 = (5/12) (x-6)
y = (5/12) x - 2.5 + 6
y = (5/12) x + 3.5
y = (5/12) x + 7/2
Answer:
the equation of the line is:
y = (5/12) x + 7/2
Using two-point slope form;
y-yo = m (x-xo)
m = (y2-y1) / (x2-x1) m = (1-6) / (- 6-6) m = 5/12
y-yo = 5/12 (x-xo)
use (6,6) as(xo,yo)
y-6 = (5/12) (x-6)
y = (5/12) x + 7/2
y-yo = m (x-xo)
m = (y2-y1) / (x2-x1) m = (1-6) / (- 6-6) m = 5/12
y-yo = 5/12 (x-xo)
use (6,6) as(xo,yo)
y-6 = (5/12) (x-6)
y = (5/12) x + 7/2