Respuesta :
1.0 M, if you're just looking for an answer.
Formula mass of AgNO3 is 107.9 + 14 + (3 X 16) = 169.9 g.
85.0 g 0.5 mole
------- = ------------ = 1.0 M
169.9 (g/mole) 0.5 liter
Formula mass of AgNO3 is 107.9 + 14 + (3 X 16) = 169.9 g.
85.0 g 0.5 mole
------- = ------------ = 1.0 M
169.9 (g/mole) 0.5 liter
Answer: 1 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{85.0g}{170g/mol}=0.5moles[/tex]
[tex]V_s[/tex] = Volume of solution in ml
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.5moles\times 1000}{500ml}=1mole/L[/tex]
Therefore, the molarity of solution will be 1 M.
