Answer:
[tex]6x^{3}+16x^{2} +6x-12[/tex]
Step-by-step explanation:
To calculate the result of that mutiplication you have to firs evaluate the first term of the second function multipying the whole first function, woudl be like this:
[tex](3x)(2x^{2}+6x+6)= 6x^{3}+18x^{2} +18x[/tex]
Now that you have this, you multiply the second term from the second function to obtain:
[tex](-2)(2x^{2}+6x+6)= -4x^{2}-12x-12[/tex]
Now you just have to add both results:
[tex]6x^{3}+18x^{2} +18x[/tex]
+ [tex] -4x^{2}-12x-12[/tex]
And the result of the sum would be:
[tex]6x^{3}+16x^{2} +6x-12[/tex]
