Respuesta :
PV = nRT
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K
(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)
n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K
(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)
n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams
Answer: 101.367 grams of chlorine gas.
Explanation:
Pressure of the chlorine gas =P = 2.85 atm
Volume occupied by the gas = 12.5 L
Temperature of the gas = 27°C= 300 K (0°C = 273 K)
Number of moles of chlorine gas = n
PV = nRT
[tex]2.85 atm\times 12.5 L=n\times 0.0820 L atm/K mol\times 300 K[/tex]
n = 1.4481 moles
Mass of the chlorine gas : 1.4481 moles × 70 g/mol = 101.367 g
101.367 grams of chlorine gas.