Respuesta :
1 mole of any substance has [tex]6.02*10^{23} particles.
So, 1.39 mol N_{2}O_{5} have
[/tex]
[tex]1.39 mol * \frac{6.02*10^{23}}{1 mol} =8.37*10^{23} molecules[/tex]
[tex]1.39 mol * \frac{6.02*10^{23}}{1 mol} =8.37*10^{23} molecules[/tex]
Explanation:
According to Avogadro's number, it is known that there are [tex]6.023 \times 10^{23}[/tex] atoms present in 1 mole of a substance.
Therefore, molecules or atoms present in 1.39 moles will be as follows.
No. of atoms = no. of moles × Avogadro's number
= [tex]1.39 moles \times 6.023 \times 10^{23}\text{atoms/mol}[/tex]
= [tex]8.37 \times 10^{23}[/tex] atoms
Thus, we can conclude that there are [tex]8.37 \times 10^{23}[/tex] atoms of dinitrogen pentoxide in 1.39 moles.
