Answer:
A. The sum of binomial is 2.
Step-by-step explanation:
We are given that two polynomials
[tex]6s^2t-2st^2[/tex]
[tex]4s^2t-3st^2[/tex]
We have to find the sum of the two polynomials
Let [tex]p=6s^2t-2st^2[/tex]
[tex]q=4s^2t-3st^2[/tex]
Adding two polynomials then we get
[tex]p+q=6s^2t-2st^2+4s^2t-3st^2[/tex]
[tex]p+q=6s^2t+4s^2t-2st^2-3st^2[/tex]
[tex]p+q=(6+4)s^2t-(2+3)st^2[/tex]
By taking common [tex]s^2t [/tex] from [tex]6s^2t\;and\; 4s^2t[/tex]
and [tex]st^2[/tex] from [tex]2st^2[/tex] and[tex] 3st^2[/tex]
Therefore, we have sum two polynomials
[tex]p+q=10s^2t-5st^2[/tex]
Binomial means the polynomial contains two terms
Therefore, the sum of binomial is '2'.
Hence , option A is true.
A. The sum of binomial is 2.
