In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.
As, Moles is given as,
Moles = Mass / M.mass
Moles = 0.53 g ÷ 283.88 g.mol⁻¹
Moles = 0.00186 moles
Now calculate the number of Molecules present in calculated moles of P₂O₅.
As,
1 Mole of P₂O₅ contains = 6.022 × 10²³ Molecules
So,
0.00186 Moles of P₂O₅ contain = X Molecules
Solving for X,
X = (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol
X = 1.12 × 10²¹ Molecules
Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....
= 1.12 × 10²¹ × 7
= 7.84 × 10²¹ Atoms
Result:
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.
