Respuesta :
Formula for slope: [tex] \frac{y2-y1}{x2-x1} [/tex]
Plug in points given: [tex] \frac{136-27}{13-2} = \frac{109}{11} = 9.9 = 9 \frac{9}{10} (Rounded) [/tex]
Slope: [tex]9.9 = 9 \frac{9}{10} [/tex]
Plug in points given: [tex] \frac{136-27}{13-2} = \frac{109}{11} = 9.9 = 9 \frac{9}{10} (Rounded) [/tex]
Slope: [tex]9.9 = 9 \frac{9}{10} [/tex]
Answer:
9.9 is the slope of the trend line drawn into the scatter plot
Step-by-step explanation:
Using slope formula:
[tex]\text{Slope} =\frac{y_2-y_1}{x_2-x_1}[/tex] ....[1]
As per the statement:
Consider two points from the given graph:
[tex](2, 27)[/tex] and (13, 136)
Substitute in [1] we have;
[tex]\text{Slope} =\frac{136-27}{13-2}[/tex]
⇒[tex]\text{Slope} =\frac{109}{11}[/tex]
Simplify:
[tex]\text{Slope} \approx 9.9[/tex]
Therefore, 9.9 is the slope of the trend line drawn into the scatter plot