A jar contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.
If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?

Question

04-04-2018
Mathematics

contestada

A jar contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.
If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?

Respuesta :

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Аноним Аноним · Answer 1 · 2018-04-04T08:20:05+02:00

Аноним Аноним

04-04-2018

Total jelly beans = 6 + 4 + 4 = 14
Total blue jelly beans = 4

Probability = 4/14 x 3/13 = 6/91

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Answer: The probability of choosing two blue jelly is 6/91.
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halimashehadeh6 halimashehadeh6 · Answer 2 · 2021-05-04T18:27:36+02:00

halimashehadeh6 halimashehadeh6

04-05-2021

Answer:

6/91

Step-by-step explanation:

khan

Answer Link

A jar contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans. If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?

Respuesta :

Otras preguntas

A jar contains 6 red jelly beans, 4 green jelly beans, and 4 blue jelly beans.
If we choose a jelly bean, then another jelly bean without putting the first one back in the jar, what is the probability that the first jelly bean will be blue and the second will be blue as well?