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abril4
The molas mass of Ba(MnO4)2 is 375.21 g/m
So what’s next it’s a simple stoichiometry conversion:)
We start with what’s given: 13.25 g and because we want to convert to moles moles will be on top and grams on the bottom. We will end up dividing 13.25 by 375.21; this gives us 0.0353 mol Ba(MnO4)2

Answer: The number of moles of given mass of barium permanganate is 0.035 moles.

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

We are given:

Given mass of barium permanganate = 13.25 g

Molar mass of barium permanganate = 375.2 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of barium permanganate}=\frac{13.25g}{375.2g/mol}=0.035mol[/tex]

Hence, the number of moles of given mass of barium permanganate is 0.035 moles.

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