Respuesta :
There are a large number of possibilities, since each box is 1 cubic foot. We do not know the exact dimensions of each box (could be 1 ft x 1 ft x 1 ft, or 2 ft x 0.5 ft x 1 ft, or 4 ft x 0.5 ft x 0.5 ft). But in the simplest case, where each box is 1 ft x 1 ft x 1 ft, some possible dimensions are:
10 ft x 16 ft x 8 ft
20 ft x 8 ft x 8 ft
5 ft x 16 ft x 16 ft
10 ft x 32 ft x 4 ft
And so on, as long as each of the storage box dimensions are divisible by the dimensions of the boxes (in this case, 1 ft)
10 ft x 16 ft x 8 ft
20 ft x 8 ft x 8 ft
5 ft x 16 ft x 16 ft
10 ft x 32 ft x 4 ft
And so on, as long as each of the storage box dimensions are divisible by the dimensions of the boxes (in this case, 1 ft)
Since [tex] 1280=2^8\cdot 5 [/tex], the dimensions (only integer) that gives the volume of the storage pod 1280 cubic feet are:
1 ft·1 ft· 1280 ft,
1 ft·2 ft· 640 ft,
1 ft·4 ft· 320 ft,
1 ft·8 ft· 160 ft,
1 ft·16 ft· 80 ft,
1 ft·32 ft· 40 ft,
1 ft·64 ft· 20 ft,
1 ft·128 ft· 10 ft,
1 ft·256 ft· 5 ft,
2 ft·2 ft· 320 ft,
2 ft·4 ft· 160 ft,
2 ft·8 ft· 80 ft,
2 ft·16 ft· 40 ft,
2 ft·32 ft· 20 ft,
2 ft·64 ft· 10 ft,
2 ft·128 ft· 5 ft,
4 ft·4 ft· 80 ft,
4 ft·8 ft· 40 ft,
4 ft·16 ft· 20 ft,
4 ft·32 ft· 10 ft,
4 ft·64 ft· 5 ft,
5 ft·8 ft ·32 ft,
5 ft·16 ft ·16 ft,
8 ft·8 ft ·20 ft,
8 ft·16 ft ·10 ft.
You can put the boxes of merchandise of volume 1 cubic foot each. If solve this question in integer numbers, then the dimensions of the box is 1 ft·1 ft· 1 ft and you can fit 1280 boxes in each storage pod listed above. If solve this question not only in integers, then there are a great amount of possible dimensions of a storage pod and boxes (for example, storage box has dimensions 0.5 ft· 2 ft· 1280 ft and boxes have dimensions 0.5 ft·2 ft· 1 ft and so on).