Answer:The net force in the net direction is 34 N.
Explanation:
Let the force from which the box is pulled be the resultant force due to horizontal and vertical components.
R = 65 N
Angle between the resultant force and the horizontal component that is force in x-direction, [tex]\theta =56^o[/tex]
Horizontal force = [tex]R\cos\theta =65 n\times 0.5299=34.44N\approx 34N[/tex]
[tex]\cos58=0.5299[/tex]
The net force in the net direction is 34 N.
