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A varying force is given by F=Ae ^-kx, where x is the position;A and I are constants that have units of N and m^-1 , respectively. What is the work done when x goes from 0.10 m to infinity?

Respuesta :

W = ∫ (x from 0.1 to +oo) F dx

= ∫ (x from 0.1 to +oo) A e^(-kx) dx

= A/k x [ - e^(-kx) ](between 0.1 and +oo)

= A/k x [ 0 + e^(-k * 0.1) ]

= A/k x e^(-k/10)

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