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A manufacturer of computer disks has a historical defective rate of .001. what is the probability that in a batch oof 1000 disks, 2 would be defective?

Respuesta :

sqdancefan
p(2 defective) = 1000C2*(.001²)*(.999⁹⁹⁸)
.. ≈ 499,500*10⁻⁶*0.368432
.. ≈ 0.18403

About 18.4%.
gavinwilliamson808

p(2 defective) = 1000C2*(.001²)*(.999⁹⁹⁸)

.. ≈ 499,500*10⁻⁶*0.368432

.. ≈ 0.18403


About 18.4%.

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