Respuesta :
If the compound is 100g
then 25.96g sulfur , 13.45g oxyegn and 59.59g chlorine.
sulfur: 25.96g/32.065g/mole=0.809moles
oxygen: 13.45g/16.0g/mole=0.84moles
chlorine: 59.59g/35.45g/mole=1.63moles
1.63:0.81:0.84
is almost
2:1:1
therefore, we can say it is
SOCl2
then 25.96g sulfur , 13.45g oxyegn and 59.59g chlorine.
sulfur: 25.96g/32.065g/mole=0.809moles
oxygen: 13.45g/16.0g/mole=0.84moles
chlorine: 59.59g/35.45g/mole=1.63moles
1.63:0.81:0.84
is almost
2:1:1
therefore, we can say it is
SOCl2
Answer:
S₄O₁Cl₈
Explanation:
Given,
Mass of S = 26.96 g
Mass of O = 13.45 g
Mass of Cl = 59.59 g
Atomic mass of S = 32.065 u
Atomic mass of O = 15.999 u
Atomic mass of Cl = 35.453 u
Moles of S = [tex]\frac{26.96 g}{32.065 u}[/tex] = 0.84
Moles of O = [tex]\frac{3.45 g}{15.999 u}[/tex] = 0.2156
Moles of Cl = [tex]\frac{59.59 g}{35.453 u}[/tex] = 1.68
Dividing by the smallest mole to get molar ratio:
[tex]\frac{0.84}{0.2156}[/tex], [tex]\frac{0.2156}{0.2156}[/tex], [tex]\frac{1.68}{0.2156}[/tex]
3.89, 1, 7.79
~ 4, 1, 8
The empirical formula is S₄O₁Cl₈