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John wants to know the volume of his gold ring in cubic centimeters. He gets a glass in the shape of a rectangular prism with a base 3\text{ cm}3 cm3, space, c, m by 2\text{ cm}2 cm2, space, c, m and fills the glass with 3.1\text{ cm}3.1 cm3, point, 1, space, c, m of water. John drops his gold ring in the glass and measures the new height of the water to be 3.7\text{ cm}3.7 cm3, point, 7, space, c, m. What is the volume of John's ring in cubic centimeters?

Respuesta :

carlosego
For this case the first thing to do is find the volume of the rectangular prism without the ring.
 We have then:
 [tex]v1 = (3) * (2) * (3.1) v1 = 18.6 cm ^ 3[/tex]
 We now look for the volume of the rectangular prism with the ring:
 [tex]v1 = (3) * (2) * (3.7) v2 = 22.2 cm ^ 3[/tex]
 Then, the volume of the ring will be the difference in volumes.
 We have then:
 [tex]v = v2 - v1 v = 22.2 - 18.6 v = 3.6 cm ^ 3[/tex]
 Answer:
 The volume of John's ring in cubic centimeters is:
 [tex]v = 3.6 cm ^ 3[/tex]

The volume of John's ring in cubic centimeters is [tex]3.6 \rm \ cm^3[/tex].

What is the volume of the ring?

The length of the rectangular prism is given by;

[tex]\rm Volume \ of \ prism =length \times breadth \times height[/tex]

The volume of the rectangular prism without the ring is;

[tex]\rm V_1=3 \times 2 \times 3.1\\\\V_1=18.6[/tex]

The volume of the rectangular prism with the ring is;

[tex]\rm V_2=3 \times 2 \times 3.7\\\\V_2=22.2[/tex]

The volume of John's ring in cubic centimeters is;

[tex]\rm V_2-V_1=22.2-18.6=3.6\\\\[/tex]

Hence, the volume of John's ring in cubic centimeters is [tex]3.6 \rm \ cm^3[/tex].

To know more about rectangular prism click the link given below.

https://brainly.com/question/13127128

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