Let s, m, L represent the number of small, medium, and Large cups of coffee Kyle filled.
s +m +L = 35 . . . . . . . . . . . . . . . served 35 cups
10s +14m +20L = 544 . . . . . . . . using 544 ounces of coffee
.95s +1.15m +1.50L = 43.60 . . . while collecting $43.60
Solving these 3 linear equations in 3 unknowns by your favorite method, you find
Kyle filled 6 small cups (10 oz)
Kyle filled 16 medium cups (14 oz)
Kyle filled 13 Large cups (20 oz)
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Elimination is a reasonable way to start. Subtract 10 times the first equation from the second, and 0.95 times the first equation from the third. Then you have
4m +10L = 194
.2m +.55L = 10.35
Now, you can subtract .05 times the first of these equation from the last to get
.05L = .65
L = 13
Back-substituting gets you the values of the other variables.