Respuesta :
Average rate of change: r=[f(b)-f(a)]/(b-a)
r=-60→[f(b)-f(a)]/(b-a)=-60
b=5; f(b)=-213; a=1; f(a)=27
(-213-27)/(5-1)=(-240)/4=-60
Answer: The two points in the table which create an interval with an average rate of change of -60 are:
x f(x)
1 27
5 -213
r=-60→[f(b)-f(a)]/(b-a)=-60
b=5; f(b)=-213; a=1; f(a)=27
(-213-27)/(5-1)=(-240)/4=-60
Answer: The two points in the table which create an interval with an average rate of change of -60 are:
x f(x)
1 27
5 -213
Answer:
1 and 5
Step-by-step explanation:
Since, the rate of change of function f(x) between a to b is [tex]\frac{f(b)-f(a)}{b-a}[/tex] or [tex]\frac{f(a)-f(b)}{a-b}[/tex]
Given,
f(1) = 27, f(2) = 21, f(3) = 3, f(4) = -51 and f(5) = -213,
Thus, the rate of change between 1 and 2 = [tex]\frac{f(2)-f(1)}{2-1}=\frac{21-27}{2}=\frac{-6}{2}=-3[/tex]
Similarly,
The rate of change, between 1 and 3 = -12,
between 1 and 4 = -26,
between 1 and 5 = -60,
between 2 and 3 = -18,
between 2 and 4 = -36,
between 2 and 5 = 78,
between 3 and 4 = -54,
between 3 and 5 = -108,
between 4 and 5 = -162
Hence, the point in the table that create an interval with the rate of change -60 are,
1 and 5.