Respuesta :
At any point on the x-axis, y = 0,
Substitute y = 0 into (x + 2) (y + 3) = 0,
(x + 2) (0 + 3) = 0
(x + 2) × 3 = 0
{Multiply each component in the bracket by 3}
3x + 6 = 0
{Make x the subject of the equation}
3x = -6
x = -2
Thus, graph intersects the x-axis at x = -2
At any point on the y-axis, x = 0,
Substitute x = 0 into equation given,
(0 + 2) (y + 3) = 0
2 × (y + 3) = 0
2y + 3 = 0
2y = -3
y = -1.5
Thus, graph intersects the y-axis at y = -1.5
Hope this helps! :)
Substitute y = 0 into (x + 2) (y + 3) = 0,
(x + 2) (0 + 3) = 0
(x + 2) × 3 = 0
{Multiply each component in the bracket by 3}
3x + 6 = 0
{Make x the subject of the equation}
3x = -6
x = -2
Thus, graph intersects the x-axis at x = -2
At any point on the y-axis, x = 0,
Substitute x = 0 into equation given,
(0 + 2) (y + 3) = 0
2 × (y + 3) = 0
2y + 3 = 0
2y = -3
y = -1.5
Thus, graph intersects the y-axis at y = -1.5
Hope this helps! :)
An equation is formed of two equal expressions. The value of x and y at which the equation will intersect the x-axis and the y-axis is -3 and -2 respectively.
What is an equation?
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
To know the point at which the equation (x+2)(y+3)=0, will intersect with the axis-x and axis-y are found by substituting the value of x and y in the equation as 0, individually.
To find the value of y at which the equation intersects the y-axis, we need to substitute the value of x as 0,
[tex](0+2)(y+3)=0\\\\(2)(y+3)=0\\\\2y+6=0\\\\y = -3[/tex]
To find the value of x at which the equation intersects the x-axis, we need to substitute the value of y as 0,
[tex](x+2)(y+3)=0\\\\(x+2)(0+3)=0\\\\x=-2[/tex]
Hence, the value of x and y at which the equation will intersect the x-axis and the y-axis is -3 and -2 respectively.
Learn more about Equation:
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