PLEASE HELP SUPER QUICK WILL GIVE BRAINLIEST AND A TON OF POINTS!!

Use the diagram and information box below to find RS,(MRT) ̂,(SV) ̂, and the area of circle R. Show your computations and/or explain how you determined each answer. A table is provided below to help you organize your work. Hint: Label the diagram using the information in the box.

Circle P and Circle R are congruent. The diameter of Circle P is 10 cm Arc MK = 50° ∠MLK =35° LM = 10 cm LK =7 cm m∠MLK = m∠SRV

It's hard to copy and paste so there are some photos.

Part a Segment RS Hint: What type of segment is RS? 5 cm RS is the Radius of circle R the diameter of circle P is 10 cm and circle R and P are congruent and a radius is half of ten so 10 / 2 = 5 cm
Part c Arc SV Hint: Read the green Arc Measures box on pg. 231. 35 * Angle SRV = 35 * Arc SV = 35 * Because the degree measure of a minor arc is the measure of it’s central angle Part d Area of Circle R Leave your answer in terms of π Hint: See the example problem on pg. 192. 25π cm Π r2= π 52 52 = 25 π
25 π cm

Аноним Аноним · Answer 2 · 2018-11-13T18:36:39+01:00

Part a Segment RS Hint: What type of segment is RS? 5 cm RS is the Radius of circle R the diameter of circle P is 10 cm and circle R and P are congruent and a radius is half of ten so 10 / 2 = 5 cm

Part c Arc SV Hint: Read the green Arc Measures box on pg. 231. 35 * Angle SRV = 35 * Arc SV = 35 * Because the degree measure of a minor arc is the measure of it’s central angle Part d Area of Circle R Leave your answer in terms of π Hint: See the example problem on pg. 192. 25π cm Π r2= π 52 52 = 25 π

25 π cm