Respuesta :
a) There are 8 possible values for each of the 3 digits, so the number of possible codes is
.. 8 * 8 * 8 = 512
b) The probability that a randomly selected code is correct is 1/512.
c) The probability it is not correct is 1 -1/512 = 511/512.
.. 8 * 8 * 8 = 512
b) The probability that a randomly selected code is correct is 1/512.
c) The probability it is not correct is 1 -1/512 = 511/512.
There are 8 possible numbers that can be inserted on the 1st, 2nd, and 3rd number of the code. Since the number can be repeated,
,
1) the number of possible access codes is 512.
Solution:
8 x 8 x 8 = 512
,
2) the probability of randomly selecting the correct access code on first try is 1/512.
.
sample space = 512
there is only 1 correct combination of numbers on the 512 possible codes so the answer is 1/512.
,
3) the probability of not randomly selecting the correct access code on first try is 511/512.
.
sample space = 512
there are 511 incorrect codes on the 512 possible codes so the answer is 511/512.
:)
,
1) the number of possible access codes is 512.
Solution:
8 x 8 x 8 = 512
,
2) the probability of randomly selecting the correct access code on first try is 1/512.
.
sample space = 512
there is only 1 correct combination of numbers on the 512 possible codes so the answer is 1/512.
,
3) the probability of not randomly selecting the correct access code on first try is 511/512.
.
sample space = 512
there are 511 incorrect codes on the 512 possible codes so the answer is 511/512.
:)