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Lee has 3 children, the oldest is twice as old as the oungest, the middle is 5 years older than the youngest, the sum of the childrens agre is 57, how old is eaach child

Respuesta :

mysticaldogg
Oldest = 2x
Middle = x + 5
Youngest = x

2x + x + 5 + x = 57
combine like terms

4x + 5 = 57
subtract 5 from both sides

4x = 52
divide both sides by 4 to isolate x

x = 13

Oldest = 2x = 2(13) = 26
Middle = x + 5 = 13 + 5 = 18
Youngest = x = 13
jpGymnastics7Books
Oldest sibling = 2x = 2(13) = 26
Middle child= x + 5 = 13 + 5 = 18
Smallest kid = x = 13

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