Respuesta :

superman1987
missing in your question the K constant value =2.99X10^-7
The reaction equation:
         SOCl2 ⇄ SO2 +Cl2
initial 0.195          0        0
         -X             +X      +X
final  (0.195-X)      X        X

K= [SO2][Cl2]/SOCl2
by substitution
2.99X10^-7 = (X)(X)/(0.195-X)
2.99X10^-7 = X^2 / (0.195-X) by solving this equation 
∴X = 0.00024 = 2.4 X10^-4 
∴[Cl2] = 2.4X10^-4 m


okpalawalter8

The equilibrium concentration of cl2 at 227C is mathematically given as

[Cl2] = 2.4X10^-4 m

Equilibrium concentration

Question Parameters:

If a reaction mixture initially contains 0.195 m so2cl2

concentration of cl2 at 227

Generally the equation for the Chemical Reaction  is mathematically given as

SOCl2 ⇄ SO2 +Cl2

Therefore

[tex]K=\frac{ [SO2][Cl2]}{SOCl2}[/tex]

2.99X10^-7 = (X)(X)/(0.195-X)

X = 0.00024 = 2.4 X10^-4

[Cl2] = 2.4X10^-4 m

For more information on Chemical Reaction

https://brainly.com/question/11231920

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