Respuesta :
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
Answer:
(6,7)
Step-by-step explanation:
The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5)
Since center is the mid point of two end points of diameter .
So, we will use mid point formula
[tex](x,y)=(4,6)[/tex]
[tex](x_1,y_1)=(2,5)[/tex]
Mid point formula : [tex]x =\frac{x_1+x_2}{2}[/tex] and [tex]y =\frac{y_1+y_2}{2}[/tex]
Substitute the values
[tex]4 =\frac{2+x_2}{2}[/tex] and [tex]6 =\frac{5+y_2}{2}[/tex]
[tex]8 =2+x_2[/tex] and [tex]12 =5+y_2[/tex]
[tex]6=x_2[/tex] and [tex]7=y_2[/tex]
Thus [tex](x_2,y_2)=(6,7)/tex]
Thus the other endpoint of the diameter is (6,7)