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Complete the tasks to subtract the polynomials vertically. (1.3t3 + 0.4t2 – 24t) – (0.6t2 + 8 – 18t) What is the additive inverse of the polynomial being subtracted? –0.6t2 + (–8) + (–18t) –0.6t2 + (–8) + 18t –0.6t2 + 8 – 18t 0.6t2 + (–8) + 18t

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boffeemadrid

Answer:

[tex]-0.6t^2-8+18t[/tex]

Step-by-step explanation:

We know that the additive inverse are two equal numbers or expressions but with different signs.

Now, the given polynomials are:

[tex](1.3t^3+0.4t^2-24t)-(0.6t^2+8-18t)[/tex]

The additive inverse is:

[tex]-0.6t^2-8+18t[/tex] which is the same expression as [tex](0.6t^2+8-18t)[/tex] but with different signs.

Thus, the additive inverse of the polynomial being subtracted is:

[tex]-0.6t^2-8+18t[/tex]

mariahjackson1289

Answer: -0.6t^2 + (-8) + 18 & the answer for the second part is "B" and the answer for the third part is 1.3t^3 - 0.2t^2 - 6t - 8

Step-by-step explanation: trust me I just did it.

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