Amare wants to ride a Ferris wheel that sits four meters above the ground and has a diameter of 50 meters. It takes six minutes to do three revolutions on the Ferris wheel. Complete the function, h(t), which models Amare's height above the ground, in meters, as a function of time, t, in minutes. Assume he enters the ride at the low point when t = 0.

Respuesta :

Answer:

The required function is [tex]h(t)=-25\cos(\pi t)+29[/tex].

Step-by-step explanation:

The general form of cosine function is

[tex]y=A\cos(Bt+C)+D[/tex]

where, A is amplitude, [tex]\frac{2\pi}{B}[/tex] is period, C is phase shift and D is midline.

It is given that the Ferris wheel that sits four meters above the ground and has a diameter of 50 meters. So the minimum value of the function is 4 and maximum value is 50+4=54.

[tex]D=\frac{Maximum+Minimum}{2}=\frac{54+4}{2}=29[/tex]

It takes six minutes to do three revolutions on the Ferris wheel. So, period of the function is

[tex]period=\frac{6}{3}[/tex]

[tex]period=2[/tex]

The period of a cosine function is

[tex]\frac{2\pi}{B}=2\Rightarrow B=\pi[/tex]

The function have no phase shift. So, C=0.

Substitute y=h(t), B=π, C=0 and D=29 in equation (1) to find the function.

[tex]h(t)=A\cos(\pi t+0)+29[/tex]

It is given that the ride is at the low point whet t=0, it means the function passes through the point (0,4).

Substitute t=0 and h(t)=4 in the above function.

[tex]4=A\cos(\pi (0)+0)+29[/tex]

[tex]4=A+29[/tex]

Subtract 29 from both the sides.

[tex]4-29=A+29-29[/tex]

[tex]-25=A[/tex]

The amplitude of the function is -25.

Substitute y=h(t), A=-25 B=π, C=0 and D=29 in equation (1) to find the function.

[tex]h(t)=-25\cos(\pi t)+29[/tex]

Therefore the required function is [tex]h(t)=-25\cos(\pi t)+29[/tex].