Respuesta :
The data has been properly arranged in tabular form and is shown below in the image.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean = [tex] \frac{97+92+89+55+90}{5}=84.6 [/tex]
Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =[tex] \frac{68+97+65+92+95}{5}=83.4 [/tex]
Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean = [tex] \frac{97+92+89+55+90}{5}=84.6 [/tex]
Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =[tex] \frac{68+97+65+92+95}{5}=83.4 [/tex]
Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
Answer:
C: The teacher should use the median for Amo and the mean for Javier 2022
Step-by-step explanation:
I took the test and please mark brainly
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