we have that
2x + 3y = 18
3x -4y > 16
Part A)
2x + 3y = 18 -------> 3y=[18-2x]---------> y=6-(2/3)x (Slope-Intercept Form)
using a graph tool
see the attached figure
the domain is the interval (-∞,∞)--------> ( all real numbers)
Domain of a function f (x) is the set of all the values of x for which the function is defined
the range is the interval (-∞,∞)--------> ( all real numbers)
Range of the function f(x) is the set of all the values that f(x) takes
Slope-Intercept Form------------> y=6-(2/3)x---------> [y=mx+b]
where
m------> is the slope------------> m=-2/3
Slope=-2/3
Y-intercept is the point for y=0
y=6-(2/3)x-------------> 0=6-(2/3)x--------> x=9
Y-intercept is the point (9,0)
Part B)
3x -4y > 16----------> -4y > 16-3x-----> y < -4+(3/4)x (Slope-Intercept Form)
using a graph tool
see the attached figure
the domain is the interval (-∞,∞)--------> ( all real numbers)
Domain of a function f (x) is the set of all the values for which the function is defined
the range is the interval (-∞,∞)--------> ( all real numbers)
Range of the function f(x) is the set of all the values that f(x) takes
Slope-Intercept Form------------> y = -4+(3/4)x---------> [y=mx+b]
where
m------> is the slope------------> m=3/4
Slope=3/4
Y-intercept is the point for y=0
y = -4+(3/4)x------------->0= -4+(3/4)x-----> 4=(3/4)x----> 16/3 = x----> x=16/3
Y-intercept is the point (5.33,0)
