The picture below shows a container that Sue uses to freeze water: A cylinder is shown with base diameter of 4 centimeters and the height as 6 centimeters. What is the minimum number of identical containers that Sue would need to make 2,000 cm3 of ice? (Use π = 3.14.) (1 point) 12 18 27 7

Respuesta :

Answer:

[tex]27\ containers[/tex]

Step-by-step explanation:

step 1

Find the volume of one container (cylinder) is equal to

[tex]V=\pi r^{2}h[/tex]

we have

[tex]r=4/2=2\ cm[/tex] -----> the radius is half the diameter

[tex]h=6\ cm[/tex]

substitute

[tex]V=(3.14)(2^{2})(6)=75.36\ cm^{3}[/tex]

step 2

By proportion

Find the the minimum number of identical containers that Sue would need to make [tex]2,000\ cm^{3}[/tex] of ice

[tex]\frac{1}{75.36}=\frac{x}{2,000}\\ \\x=2,000/75.36\\ \\x= 26.5\ containers[/tex]

Round to the nearest whole number

[tex]26.5=27\ containers[/tex]

Answer: 27

Step-by-step explanation:

Given: The height of the cylindrical container = 6 cm

Diameter of container = 4 cm

Then the radius of the container = [tex]\frac{4}{2}=[/tex]2 cm

Now, the volume of the cylindrical container is given by :-

[tex]\text{Volume}=\pi r^2 h\\\\\Rightarrow\text{Volume}=(3.14)(2)^2(6)=75.3982236862\approx75.4\ cm^3[/tex]

Now, the minimum number of identical containers that Sue would need to make 2,000 [tex]cm^3[/tex] of ice is given by:-

[tex]\frac{2000}{75.4}=26.525198939\approx27[/tex]

Hence, the minimum number of identical containers that Sue would need to make 2,000 [tex]cm^3[/tex] of ice is 27.