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What is the total amount of work required to
move a proton through a potential difference of
100. volts?
(1) 1.60 × 10^–21 J (3) 1.00 × 10^2 J
(2) 1.60 × 10^–17 J (4) 6.25 × 10^20 J

Respuesta :

Answer:

[tex]W = 1.6 \times 10^{-17} J[/tex]

Explanation:

Work done to move a charge through a given potential difference is

[tex]W = q(\Delta V)[/tex]

here

q = magnitude of charge

[tex]\Delta V [/tex] = potential difference

here it is given that charge of the particle is same as charge of proton

[tex]q = 1.6 \times 10^{-19} C[/tex]

[tex]\Delta V = 100 V[/tex]

now we have

[tex]W = (1.6 \times 10^{-19}) (100)[/tex]

[tex]W = 1.6 \times 10^{-17} J[/tex]

Pokecobrajoe03

Answer:

Number 2

Explanation:

Elementary Charge x volts given

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