Respuesta :
Standard enthalpy of combustion is the enthalpy change for one mole of a substance that burns or combines with the oxygen under the standard state conditions that is 1 bar pressure and  temperature.
Answer:
Energy released = 2832.79 kJ
Explanation:
The standard enthalpy of the combustion of methanol, [tex]\Delta\ H^0=-726.1\ kJ/mol[/tex]
It means that :
1 mole of methanol on combustion releases 726.1 kJ of energy
Molar mass of methanol = 32.04 g/mol
Thus, mass of 1 mole of methanol is 32.04 g
So,
32.04 g of methanol on combustion releases 726.1 kJ of energy
1 g of methanol on combustion releases 726.1/32.04 kJ of energy
125 g of methanol on combustion releases (726.1/32.04)*125 kJ of energy
Energy released = 2832.79 kJ
