Respuesta :
so the square was fine, then the triangle decided to go for a hike.
now, if the triangle when it took off, it took 59 cm², and the square was left all by its lonesome with only 85 cm², that means with the triangle in it, the square is then 59 + 85 cm², or 144 cm².
[tex]\bf \textit{area of a square}\\\\ A=s^2\qquad \begin{cases} s=\textit{length of a side}\\ ---------\\ A=144 \end{cases}\implies 144=s^2 \\\\\\ \sqrt{144}=s \implies 12=s[/tex]
now, if the triangle when it took off, it took 59 cm², and the square was left all by its lonesome with only 85 cm², that means with the triangle in it, the square is then 59 + 85 cm², or 144 cm².
[tex]\bf \textit{area of a square}\\\\ A=s^2\qquad \begin{cases} s=\textit{length of a side}\\ ---------\\ A=144 \end{cases}\implies 144=s^2 \\\\\\ \sqrt{144}=s \implies 12=s[/tex]
To obtain the length of the side of a square we need to find the Area of the square. The area of the square is square of their sides.
The length of side is 12 cm.
Given:
The area of triangle is [tex]59\:\rm cm^2[/tex].
The remaining area is [tex]85\:\rm cm^2[/tex].
Calculate the complete area of square before cut.
[tex]\rm {Total\: area\: of \:circle}=Area\: of \:circle +Remaining\: area \:of\: square\\\rm {Total\: area\: of \:circle}=59+85\\\rm {Total\: area\: of \:circle}=144\:\rm cm^2[/tex]
Write the formula for area of circle.
[tex]A=s^2[/tex]
Where [tex]s[/tex] is sides of square.
[tex]144=s^2\\\sqrt{144}=s\\s=12\:\rm cm[/tex]
Thus, the length of side is 12 cm.
Learn more about area of circle here:
https://brainly.com/question/21287691
