The school band sells carnations on Valentine’s Day for $3 each. It buys the carnations from a florist for $0.50 each, plus a $18 delivery charge. When will the cost of the carnations be equal to the revenue from selling them? How many carnations does it need to sell to reach this point?

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vicky93 vicky93

04-02-2018
Mathematics

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The school band sells carnations on Valentine’s Day for $3 each. It buys the carnations from a florist for $0.50 each, plus a $18 delivery charge. When will the cost of the carnations be equal to the revenue from selling them? How many carnations does it need to sell to reach this point?

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Dibny Dibny · Answer 1 · 2018-02-09T13:08:28+01:00

Let's denote the number of carnations as x. We can express the revenue as [tex]3x[/tex] and the cost as [tex]0.50x+18[/tex].

To find when the cost and revenue will be equal, we just equate the two expressions. We need to solve for x to find the number of carnations needed to reach that point.

[tex]3x=0.50x+18[/tex]
[tex]2.50x=18[/tex]
[tex]x=7.2[/tex]

For the revenue to be equal, the number of carnations sold should be equal to 7.2, BUT, realistically speaking, we can never have 0.2 of a carnation. So, the cost of the carnations will NEVER equal the revenue of selling them. 7 carnations sold would have a slightly smaller revenue compared to the cost and 8 carnations sold would have a larger revenue.