Here the multiplication of the expression given,
[tex] -\frac{3}{7}xy(-35x^3y^2) [/tex]
To multiply the expression first we have to multiply the signs negative and negative. We know that negative times negative will give positive.
[tex] (-)(-)\frac{3}{7}xy(35x^3y^2) [/tex] = [tex] +\frac{3}{7}xy(35x^3y^2) [/tex]
Now we will multiply the numbers [tex] \frac{3}{7} [/tex] and 35.
[tex] (\frac{3}{7} )(35) xy(x^3y^2) [/tex]
= [tex] \frac{(3)(35)}{7}xy(x^3y^2) [/tex]
= [tex] \frac{105}{7} xy(x^3y^2) [/tex]
= [tex] 15xy(x^3y^2) [/tex]
Now we will multiply x with x and y with y. We will use properties of exponent. We know that when base is same, we have to add the exponents only. If we have [tex] (x^m)(x^n) = x^{(m+n)} [/tex].
So here x means [tex] x^1 [/tex].
Multiplying we will get here,
[tex] 15xy(x^3y^2) = 15x^1y^1(x^3y^2) [/tex]
= [tex] 15x^{(1+3)}y^{(1+2)} [/tex]
= [tex] 15x^4y^3 [/tex]
We have got the required answer here.
