During a recent eruption, a piece of ash was ejected from a volcano with an initial velocity of 368 ft/sec.

The height (H), in feet, of our ash projectile is given by the equation
H=16t^2 + 368t

Where t is time, in seconds.

The graph of the equation will be a parabola
Assume the volcano does not have a height. So, H= 0 and t=0

1.) when does the ash projectile reach it's maximum height?
2.)What is the maximum height?
3.)When does the ash projectile return to the ground?