Jasmine bought 1.3 pounds of ham and 0.8 pounds of cheese from the deli and paid $11.28. She went back the following week and bought 1.5 pounds of ham and 1.2 pounds of cheese and paid $14.76. If the prices remained the same, find the price per pound of ham and cheese using the elimination method

Let

x be the price for a pound of ham
y the price for a pound of cheese

1.3x +0.8y = 11.28 ....(1)
1.5x +1.2y = 14.76 ....(2)

Lets multiply (1) by -1.2
Lets multiply (2) by 0.8

-1.56x -0.96y = -13.536 .....(3)
1.2x + 0.96y = 11.808 .....(4)

If we add (3) and (4)

-0.36x = -1.728 ............> x = 4.8

We substitute in (1)

1.3(4.8) +0.8y = 11.28

y = 6.3

Price per pound of ham = x = 4.8
Price per pound of cheese = y = 6.3

Answer Link

ahirohit963 ahirohit963 · Answer 2 · 2021-10-25T14:17:10+02:00

Price per pound of ham is 4.8

Price per pound of cheese is 6.3

Given :

Jasmine bought 1.3 pounds of ham and 0.8 pounds of cheese from the deli and paid $11.28.

She went back the following week and bought 1.5 pounds of ham and 1.2 pounds of cheese and paid $14.76.

Solution :

Let 'a' be the price of one pound of ham and 'b' be the price of one pound of cheese.

From the given data we have,

1.3a + 0.8b = 11.28 ---- (1)

1.5a + 1.2b = 14.76 ---- (2)

Now from equation (1),

[tex]\rm a = \dfrac{11.28-0.8b}{1.3}[/tex] ----- (3)

Now from equation (2) and (3) we get,

[tex]\rm 1.5\times (\dfrac{11.28-0.8b}{1.3}) +1.2b=14.76[/tex]

[tex]\rm 1.15(11.28-0.8b) + 1.2b = 14.76[/tex]

[tex]\rm 12.97-0.92b+1.2b = 14.76[/tex]

[tex]\rm 0.28\;b = 1.79[/tex]

b = 6.3

Now put the value of b in equation (3) we get,

[tex]\rm a = \dfrac{11.28-0.8(6.3)}{1.3}[/tex]

a = 4.8

Price per pound of ham is 4.8

Price per pound of cheese is 6.3

For more information, refer the link given below

https://brainly.com/question/25018625?referrer=searchResults