Respuesta :
Answer:
[tex]H_2O_2[/tex] is the compound's molecular formula.
Explanation:
Let the molecular formula of the compound be [tex]H_xO_y[/tex]
Molar mass of the compound = 34.02 g/mol
Atomic mass of hydrogen atom = 1.00 g/mol
Atomic mass of an oxygen atom = 16.00 g/mol
Percentage of hydrogen in compound = 5.94%
Percentage of an oxygen in compound = 100% - 5.94% = 94.06 %
Percentage of hydrogen :
[tex]5.94\%=\frac{x\times 1.00 g/mol}{34.02 g/mol}\times 100[/tex]
x =2.02 ≈ 2
Percentage of oxygen:
[tex]94.06\%=\frac{y\times 16.00 g/mol}{34.02 g/mol}\times 100[/tex]
y = 1.99 ≈ 2
The compound's molecular formula: [tex]H_xO_y=H_2O_2[/tex]
[tex]H_2O_2[/tex] is the compound's molecular formula.
