Respuesta :

[tex] \frac{1}{3} (2x-4)+5=- \frac{2}{3}(x + 1) \\ \\ \frac{2x-4}{3} +5=- \frac{2}{3} (x + 1) \\ \\ \frac{2x-4}{3} +5=- \frac{2(x + 1)}{3} \\ \\ 2(x - 2) + 15 = -2(x + 1) \\ \\ 2x - 4 + 15 = -2x - 2 \\ \\ 2x + 11 = -2x - 2 \\ \\ 2x + 11 + 2x = -2 \\ \\ 4x + 11 = -2 \\ \\ 4x = -2 - 11 \\ \\ 4x = -13 \\ \\ x = - \frac{13}{4} \\ \\ Answer: \fbox {x = -13/4} \ or \ \fbox {-3.25} [/tex]
TSO
[tex]\frac{1}{3}(2x-4)+5=-\frac{2}{3}(x+1)\\\\3 \times[ \frac{1}{3}(2x-4)+5] = 3\times -\frac{2}{3}(x+1)\\\\(2x-4) + 15 = -2(x+1)\\\\2x - 4 + 15 = -2(x+1)\\\\2x + 11 = -2(x+1) \\\\2x + 11 = -2x -2\\\\4x + 11 = -2\\\\4x = -13\\\\\boxed{\bf{x = -\frac{13}{4}}}[/tex]