Answer:
[tex]\frac{-3x^2}{2y^2} * \frac{y^2}{9x}=\frac{-1}{6}x[/tex]
[tex]\frac{5y^2}{10x^2} * \frac{4x^2}{y}= 2y[/tex]
[tex]\frac{-9y^2}{5x} * \frac{-10x^2}{3y}=6xy[/tex]
[tex]\frac{14x^2}{5y} * \frac{-10y}{7x}=-4x[/tex]
Step-by-step explanation:
(1) [tex]\frac{-3x^2}{2y^2} * \frac{y^2}{9x}[/tex]
cancel out y^2 at the top and bottom
x^2/x = x and -3/2*9 is -1/6
[tex]\frac{-3x^2}{2y^2} * \frac{y^2}{9x}=\frac{-1}{6}x[/tex]
(2) [tex]\frac{5y^2}{10x^2} * \frac{4x^2}{y}[/tex]
y^2/y= y, x^2 cancelled out
5*10 / 4= 2
[tex]\frac{5y^2}{10x^2} * \frac{4x^2}{y}= 2y[/tex]
(3) [tex]\frac{-9y^2}{5x} * \frac{-10x^2}{3y}[/tex]
x^2/x= x and y^2/y=y
90/15 =6
[tex]\frac{-9y^2}{5x} * \frac{-10x^2}{3y}=6xy[/tex]
(4) [tex]\frac{14x^2}{5y} * \frac{-10y}{7x}[/tex]
x^2/x= x, cancel out y
14/7 = 2 , -10/5 = -2
[tex]\frac{14x^2}{5y} * \frac{-10y}{7x}=-4x[/tex]
