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The ages of three friends are consecutively one year apart. Together their ages total 48 years. Which equation can be used to find the age of each friend (where a represents the age of the youngest friend)?
A. 3a=48
B. a(a+1)(a+2)=48
C. a+(a-1)+(a-2)=48
D. a+(a+1)+(a+2)=48

Respuesta :

texaschic101
three consecutive numbers....a, a + 1, a + 2
together their ages total 48 years

a + (a + 1) + (a + 2) = 48 <== ur equation
3a + 3 = 48
3a = 48 - 3
3a = 45
a = 45/3
a = 15

a + 1 = 15 + 1 = 16
a + 2 = 15 + 2 = 17

so their ages are : 15,16,17
Lanuel

An equation which can be used to find the age of each friend is: D. a + (a+1) + (a+2) =48

  • Let a be the age of the youngest friend.

Given the following data:

  • Total age = 48 years

To write an equation which can be used to find the age of each friend:

Since the ages of the three friends are consecutively one year apart, it simply means that the difference between their ages is one (1) respectively and in an ascending order:

For the younger friend (second):

[tex]Age = (a+1)\;years[/tex]

For the young friend (third):

[tex]Age = (a+1)\;years[/tex]

Evaluating as an equation, we have:

[tex]Age = a+(a+1)+(a+2)=48[/tex]

Read more on age here: https://brainly.com/question/6463206

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