Answer is: 12,8 l of H₂SO₄.
Chemical reaction: H₂SO₄ + Na₂CO₃ → Na₂SO₄ + CO₂ + H₂O.
m(H₂O) = 150 g.
c(H₂SO₄) = 0,650 mol/dm³.
V(H₂SO₄) = ?
n(H₂O) = m(H₂O) ÷ M(H₂O)
n(H₂O) = 150 g ÷ 18 g/mol = 8,33 mol.
from reaction: n(H₂SO₄) : n(H₂O) = 1 : 1.
n(H₂SO₄) = 8,33 mol.
c = n ÷ V, V = n ÷ c.
V(H₂SO₄) = 8,33 mol ÷ 0,650 mol/dm³ = 12,81 dm³.