Respuesta :
2 weeks ago, oh boy.
So we know k is 10 N/m and it is stretch 0.1m.
For the conservation of energy, we know the mechanical energy in the system is constant, and we know the energy switches from potential elastic energy to kinetic energy. So we can solve for the maximum potential elastic energy, which should tell us the mechanical energy.
Since we are told it is stretch 0.1m and we are given the spring constant, we can solve for max potential elastic energy.
Mechanical energy = Max potential = 0.5kA^2
This gives us 0.5(10N/m)(0.1m)^2 = 0.05J
The maximum kinetic energy is when the potential elastic energy is zero, thus 0.05J would be the maximum kinetic energy.
Hope this helps!
So we know k is 10 N/m and it is stretch 0.1m.
For the conservation of energy, we know the mechanical energy in the system is constant, and we know the energy switches from potential elastic energy to kinetic energy. So we can solve for the maximum potential elastic energy, which should tell us the mechanical energy.
Since we are told it is stretch 0.1m and we are given the spring constant, we can solve for max potential elastic energy.
Mechanical energy = Max potential = 0.5kA^2
This gives us 0.5(10N/m)(0.1m)^2 = 0.05J
The maximum kinetic energy is when the potential elastic energy is zero, thus 0.05J would be the maximum kinetic energy.
Hope this helps!
The maximum kinetic energy at any time will be 0.05J.
Given that the spring constant K = 10 N/m
displacement of spring x = 0.1 m
Now, the total mechanical energy of the system remains conserved, that is:
E = KE + PE
where KE is kinetic energy and PE is potential energy
This implies that when KE is max = E. PE = 0 and when PE is max = E, KE = 0
Maximum value of E = PE(max) = KE(max)
PE(max) =KE(max)
KE(max) = [tex]\frac{1}{2}kx^2[/tex]
KE(max) = 1/2 × 10 × 0.1 × 0.1 J
KE(max) = 0.05 J is the maximum kinetic energy of the system
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