Answer:
This question is incomplete, the completed question is below.
- Which quantity is equivalent to 39 grams of LiF?
(a) 1.0 mole
(b) 2.0 mole
(c) 0.50 mole
(d) 1.5 mole
The correct option is d
Explanation:
LiF is Lithium flouride. Lithium (Li) has a molar mass of 7 g/mol while flourine (F) has a molar mass of 19 g/mol. Hence, 1 mole of LiF will be
7 + 19 = 26 g/mol
If 1 mole of LiF = 26g,
X mole of LiF = 39g
When you cross multiply, you will have
X mole x 26g = 1 mole x 39g
make X the subject and you will have
X mole = 1 mole x 39g/26g
X mole = 1.5 mole
Hence, 1.5 mole of LiF is equivalent to 39 grams of LiF
