Respuesta :
so the coordinates are written (x,y) so if you have a graph you would oput the first dot at 1 over,2 up as x avis is the horizontal axis and y is vertical, then your next dot would be three over ,10 up and then your last dot would be 5 over and 18 up, your intercept is where your line meets your axis
Let's first find the equation of the line in the slope-intercept form, y = mx + b.
First, we find the slope.
m = (y2 - y1)/(x2 - x1) = (10 - 2)/(3 - 1) = 8/2 = 4
The slope is 4.
y = mx + b
y = 4x + b
Now we need to find b.
We start with y = 4x + b, and use the point (1, 2) for x and y.
2 = 4(1) + b
2 = 4 + b
b = -2
The equation is
y = 4x - 2
Now we can find the intercepts.
The x-intercept is where the line crosses the x-axis. There, the y-coordinate is 0. We set y = 0, and solve for x.
y = 4x - 2
0 = 4x - 2
-4x = -2
x = 1/2
The x-intercept is (1/2, 0).
The y-intercept is where the line crosses the y-axis. There, the x-coordinate is 0. We set x = 0, and solve for y.
y = 4x - 2
y = 4(0) - 2
y = 0 - 2
y = -2
The y-intercept is (0, -2).
First, we find the slope.
m = (y2 - y1)/(x2 - x1) = (10 - 2)/(3 - 1) = 8/2 = 4
The slope is 4.
y = mx + b
y = 4x + b
Now we need to find b.
We start with y = 4x + b, and use the point (1, 2) for x and y.
2 = 4(1) + b
2 = 4 + b
b = -2
The equation is
y = 4x - 2
Now we can find the intercepts.
The x-intercept is where the line crosses the x-axis. There, the y-coordinate is 0. We set y = 0, and solve for x.
y = 4x - 2
0 = 4x - 2
-4x = -2
x = 1/2
The x-intercept is (1/2, 0).
The y-intercept is where the line crosses the y-axis. There, the x-coordinate is 0. We set x = 0, and solve for y.
y = 4x - 2
y = 4(0) - 2
y = 0 - 2
y = -2
The y-intercept is (0, -2).