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In ΔABC, m∠CAB = 60° and AD is an angle bisector with D ∈BC and AD = 8 ft.
Find the distances from D to the sides of the triangle.

Respuesta :

shinmin
This tells us that point D is in the line of BC, which is opposed angle CAB. We are asked to find the distances from D to the sides of the triangle.
So we have,
tan (30) = DB / ADtan (30) = DB / 8DB = 8 * tan(30)DB = 4.61880215352
So, the correct answer for this question is 4.62

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