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Set up the following application problem and don't forget to declare your variable. Round to 2 decimal points.

There is a moving sidewalk that moves at the speed of 2ft/sec.
As Larry walks on that sidewalk, he notices that he can travel 110 ft with the sidewalk, in the same time that it would take for him to travel 80ft in the opposite direction.

What is Larry's normal walking speed (without the moving sidewalk speed, 2ft/sec)

Respuesta :

jorel1380
Let w equal Larry's walking speed. Then:
110/w+2=80/w-2
80w+160=110w-220
30w=380
w=12.67 ft/sec as Larry's walking speed
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mreijepatmat
Reminder; time = Distance/Speed
a)If his walking speed is "s" and the moving sidewalk is 2, then the speed of the whole will be s+2
b) On his way back, his speed is always s, but the moving sidewalk is (- 2), then his total speed on his way back will be s-2
Now let bring it in an equation. Note that he spent the same time in both direction (only the distance changed):

time = 110/(2+s) = 80/(s-2)
Solving it will give s = 12.666 ft/s
or s= 12.67 ft/s

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