Solution:
In Δ C DA and in ΔB DA,
As, image of the problem is not given, there are two ways in which image of the problem can be drawn describing the problem.
∠BDA=90° →→Given
→∠C = ∠B→→[Given]
→Side AD is common between two triangles.
and ,→Either→∠ BDA=∠CDA=90° ∨ or →∠B DA=∠CA D=90° .
→Δ C DA ≅ ΔB DA,→→[S AS]
Option (B) Yes, Δ C DA ≅ ΔB DA, by SAS criterion.
